Answer:
Option C
Explanation:
In XeF2 ,total number of valence electrons of Xe=8,2 electrons are shared with 2F atoms,6 electrons are left hence 3 lone pairs.
In XeF4 ,total number of valence electrons of Xe=8,4 electrons are shared with 4F atoms ,4 electrons are left hence 2 lone pairs.
In XeF6 , total number of valence electrons of Xe=8,6 electrons are shared with 6F atoms ,2 electrons are left hence 1 lone pair.