Chemistry | VITEEE 2018 | Discussion Page

In the series of reaction

$C_{6}H_{5}NH_{2} \xrightarrow[{0-5^{\circ}C}]{NaNO_{2}/HCl}X\xrightarrow[{H_{2}O}]{HNO_{2}}Y +N_{2}+HCl$

X and Y are Respectively

$C_{6}H_{5}-N=N-C_{6}H_{5},C_{6}H_{5}N_2^\oplus Cl^{\ominus}$

$C_{6}H_{5}N_2^\oplus Cl^{-},C_{6}H_{5}-N=N-C_{6}H_{5}$

$C_{6}H_{5}N_2^\oplus Cl^{-},C_{6}H_{5}NO_{2}$

$C_{6}H_{5}NO_{2},C_{6}H_{6},$

Option C

$C_{6}H_{5}NH_{2} \xrightarrow[{0-5^{\circ}C}]{NaNO_{2}/HCl}C_{6}H_{5}N_2^+ Cl^{-}\xrightarrow[{H_{2}O}]{HNO_{2}}C_{6}H_{5}NO_{2} +N_{2}+HCl$

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