Discussion Forum



1)

In XeF2, XeF4, XeF6 the number of lone pairs on Xe are respectively


A) 2,3,1

B) 1,2,3

C) 4,1,2

D) 3,2,1

Answer:

Option C

Explanation:

In XeF2 ,total number of valence electrons of Xe=8,2 electrons are shared with 2F atoms,6 electrons are left hence 3 lone pairs.

In XeF4 ,total number of valence electrons of Xe=8,4 electrons are shared with 4F atoms ,4 electrons are left hence 2 lone pairs.

In XeF6 , total number of valence electrons of Xe=8,6 electrons are shared with 6F atoms ,2 electrons are left hence 1 lone pair.