Discussion Forum



1)

For the reaction :

$2 BaO_{2}(s)\rightleftharpoons2BaO(s) + O_{2}(g);$

ΔH = +ve. In equilibrium condition, pressure of O2 is dependent on


A) $mass of BaO_{2}$

B) mass of BaO

C) temperature of equilibrium

D) $mass of BaO_{2} and BaO both$

Answer:

Option C

Explanation:

For the reaction

$2 BaO_{2}(s)\rightleftharpoons2BaO(s) + O_{2}(g);$ ΔH = + ve.

In equilibrium Kp = Po2

Hence, the value of the equilibrium constant depends only upon partial pressure of O2. Further on increasing temperature formation of O2 increases as this is an endothermic reaction. Hence, pressure of O2 is dependent on temperature