Data Interpretation :: Tabulation :: Tabulation 9

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What is the number of candidates passing the exam from City E ?

Answer:

Explanation:

Number of candidates passing the exam from City E

= $\left(1.85\times100000\times\frac{3}{5}\right)$

= $\left(\frac{185000\times3}{5}\right)$

= $\left(37000\times3\right) = 111000$

Which city has the highest number of students failing the entrance exam ?

Answer:

Explanation:

Number of failures from different cities :

A → $\left(1.25\times100000\times\frac{3}{10}\right) = 37500$

B → $\left(3.14\times100000\times\frac{3}{8}\right)$

= $\left(\frac{314000\times3}{8}\right) = 117750$

C → $\left(1.08\times100000\times\frac{5}{9}\right)$

= $\left(\frac{108000\times5}{9}\right) = 60000$

D → $\left(2.27\times100000\times\frac{3}{4}\right)$

= $\left(\frac{227000\times3}{4}\right) = 170250$

E → $\left(1.85\times100000\times\frac{2}{5}\right)$

= $\left(\frac{185000\times2}{5}\right) = 74000$

F → $\left(2.73\times100000\times\frac{5}{12}\right) $

= $\left(\frac{273000\times5}{12}\right) = 113750$

So, the maximum number of failures are from City D.

The number of candidates passing the examination from City F is what percent of the total number of candidates appearing from all the cities together ? (rounded off to two digit after the decimal).

Answer:

Explanation:

Total number of candidates from all the 5 cities

= [(1.25 + 3.14 + 1.08 + 2.27 + 1.85 + 2.73) x 100000] = (12.32 x 100000) = 1232000.

Number of candidates passing the exam from City F

= $\left(\frac{7}{12}\times2.73\times100000\right)$

= $\left(\frac{7\times273\times1000}{12}\right)$

= $\left(7\times91\times250\right) = 159250$

Required Percentage = $\left(\frac{159250}{1232000}\times100\right)$%

= $\left(\frac{15925}{1232}\right)$% = 12.926 = 12.93%

The number of candidates appearing for the exam from City C is what percent of the number of candidates appearing for the exam from City B ? (rounded off to nearest integer)

Answer:

Explanation:

Number of candidates from city C = (1.08 x 100000) = 108000.

Number of candidates from city B = (3.14 x 100000) = 314000.

Required percentage = $\left(\frac{108000}{314000}\times100\right)$%

= $\left(\frac{108}{314}\times100\right)$%

= $\left(\frac{54}{157}\times100\right)$%

= $\frac{5400}{157} $% = 34.39% = 34%

What is the ratio of the number of candidates failing the exam from City D to that of those failing the exam from City A ?

Answer:

Explanation:

Number of candidates failing from city D

= $\left(\frac{3}{4}\times2.27\times100000\right)$

= $\left(\frac{3}{4}\times\frac{227}{100}\times100000\right)$

= $\left(227\times750\right)$

Number of candidates failing from city A

= $\left(\frac{3}{10}\times1.25\times100000\right)$

= $\left(\frac{3}{10}\times\frac{125}{100}\times100000\right)$

= $\left(300\times125\right)$

Required ratio : $\left(\frac{227\times750}{300\times125}\right)$

= $\frac{227}{50}= 227:50$

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