Discussion Forum

The number of candidates appearing for the exam from City C is what percent of the number of candidates appearing for the exam from City B ? (rounded off to nearest integer)

Answer:

Explanation:

Number of candidates from city C = (1.08 x 100000) = 108000.

Number of candidates from city B = (3.14 x 100000) = 314000.

Required percentage = $\left(\frac{108000}{314000}\times100\right)$%

= $\left(\frac{108}{314}\times100\right)$%

= $\left(\frac{54}{157}\times100\right)$%

= $\frac{5400}{157}$% = 34.39% = 34%