Discussion Forum

The number of candidates passing the examination from City F is what percent of the total number of candidates appearing from all the cities together ? (rounded off to two digit after the decimal).

Answer:

Explanation:

Total number of candidates from all the 5 cities

= [(1.25 + 3.14 + 1.08 + 2.27 + 1.85 + 2.73) x 100000] = (12.32 x 100000) = 1232000.

Number of candidates passing the exam from City F

= $\left(\frac{7}{12}\times2.73\times100000\right)$

= $\left(\frac{7\times273\times1000}{12}\right)$

= $\left(7\times91\times250\right) = 159250$

Required Percentage = $\left(\frac{159250}{1232000}\times100\right)$%

= $\left(\frac{15925}{1232}\right)$% = 12.926 = 12.93%