Answer:
Option D
Explanation:
Number of failures from different cities :
A → $\left(1.25\times100000\times\frac{3}{10}\right) = 37500$
B → $\left(3.14\times100000\times\frac{3}{8}\right)$
= $\left(\frac{314000\times3}{8}\right) = 117750$
C → $\left(1.08\times100000\times\frac{5}{9}\right)$
= $\left(\frac{108000\times5}{9}\right) = 60000$
D → $\left(2.27\times100000\times\frac{3}{4}\right)$
= $\left(\frac{227000\times3}{4}\right) = 170250$
E → $\left(1.85\times100000\times\frac{2}{5}\right)$
= $\left(\frac{185000\times2}{5}\right) = 74000$
F → $\left(2.73\times100000\times\frac{5}{12}\right) $
= $\left(\frac{273000\times5}{12}\right) = 113750$
So, the maximum number of failures are from City D.
