Answer:
Option C
Explanation:
Consider the potential at D be 'V'.
Potential drop across C1 is (V - V1) and C2 is (V - V)
.'. q1 = C1 (V - V1), q2 = C2 (V2 - V)
As q1 = q2 [capacitors are in series]
.'. C1 (V - V1) = C2 (V2 - V)
V = $\frac{C_{1}V_{1}+C_{2}V_{2}}{C_{1}+C_{2}}$