Answer:
Option A
Explanation:
The maximum velocity of body in SHM
v= A \omega
where , A is amplitude of body and \omega is the angular frequency.
It is given that , the maximum velocities of bodies are equal
V_{A}=V_{B}
A_{A}\omega_{A}=A_{B}\omega_{B}
A_{A}\sqrt{\frac{k_{1}}{m}}=A_{B}\sqrt{\frac{k_{2}}{m}}
\left(\because \omega =\sqrt{\frac{k}{m}}\right)
\frac{A_{A}}{A_{B}}=\sqrt{\frac{k_{2}}{k_{1}}}