Physics | MHT CET 2020 | Discussion Page

The Brewster's angle for the glass-air interface is (54.74) °. If a ray of light passing from air to glass strikes at an angle of incidence 45°, then the angle of refraction is

$[\tan (54.74)^{0}=\sqrt{2},\sin 45=\frac{1}{\sqrt{2}}]$

$\sin ^{-1}\left(\sqrt{2}\right)$

$\sin ^{-1}\left(1\right)$

$\sin ^{-1}\left(0.5\right)$

$\sin ^{-1}\left(\frac{0.5}{\sqrt{2}}\right)$

Answer:

Option C

Explanation:

According to Brewster'law , refarctive index of glass

$\mu_{2}=\tan(i_{p})$

= $\tan (54.74)^{0}$ = $\sqrt{2}$

From Snell's law,

$\mu_{1}\sin i=\mu_{2}\sin r$

$1\times \sin(45^{0})=\sqrt{2}\sin r$

$\frac{1}{\sqrt{2}\times\sqrt{2}}=\sin r$

sin r=0.5

r = sin^-1 (0.5)

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Answer:

Explanation: