Answer:
Option C
Explanation:
Equation of plane parallel to the plane
x+2y+2z+8=0 is x+2y+2z+λ=0
Given distance from the point (1,1,2) to the plane.
x+2y+2z +$\lambda$=0 is 2 units
$\therefore$ $2=|\frac{1+2+4+\lambda}{\sqrt{1+4+4}}|$
$\Rightarrow$ $ \pm2=\frac{\lambda+7}{3}$
$\Rightarrow \lambda+7=\pm6$
$\therefore$ $\lambda$ = -13,-1
Hence , equation of plane is
x+2y+2z-13=0 or x+2y+2z-1=0