Discussion Forum

 The equation of the directrix  of the parabola 3x²=16y is 

Answer:

Explanation:

 Given  parabola,   3x²=16y

$x^{2}=\frac{16}{3}y$

 Here,    $4a=\frac{16}{3}$

 $a=\frac{4}{3}$

 equation of directrix of parabola,

    x² = 4ay is

 y+a=0

 $\therefore$     Equation of directris of parabola,.

 $x^{2}=\frac{16}{3}y$

  $y+\frac{4}{3}=0$

 3y+4=0