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For  a common emitter configuration if α and β  have their  usual meaning the incorrect relationship between α and β is

Answer:

Explanation:

$I_{b}+I_{C}=I_{e}$

$\Rightarrow \frac{I_{b}}{I_{c}}+1=\frac{I_{e}}{I_{c}}$

$\Rightarrow \frac{1}{\beta}+1=\frac{1}{\alpha}\Rightarrow \frac{1}{\alpha}=\frac{1+\beta}{\beta}$

$\Rightarrow \frac{\beta}{1+\beta}$

Identify the semiconductor devices whose characteristics are as given below, in the order (a),(b), (c), (d)

Answer:

Explanation:

  Theoretical question. Therefore no solution is required

In an experiment for determination of the refractive index of a glass of a prism by i-δ plot, ut was found that a ray incident at an angle 35° suffers a deviation of 40° and that it emerges at an angle 79⁰, In that case, which of the following is closest to the maximum possible value of the refractive index?

Answer:

Explanation:

$\delta = (i_{1}+i_{2})-A$

   $\Rightarrow 40^{0}=(35^{0}+79^{0})-A$

 $\Rightarrow  A=74^{0}$

Now, we know that  $\mu = \frac{\sin(\frac{A+\delta_{m}}{2})}{\sin(\frac{A}{2})}$

It  we take the given deviation as the minimum  deviation then,

$\mu = \frac{\sin(\frac{74^{0}+40^{0}}{2})}{\sin(\frac{74^{0}}{2})}$ = 1.51

The given deviation may or may not be the minimum deviation. Rather it will be less than this value. Therefore  μ  will be less than 1.51

  Hence , the maximum possible value of refractive index is 1.51

A galvanometer having a coil resistance of 100 Ω gives a full-scale deflection when a current of 1 mA is passed through it. The value of the resistance which can convert this galvanometer into ammeter giving a full-scale deflection for a current of 10 A is 

Answer:

Explanation:

 In parallel, current distributes in inverse ratio of resistance

 Hence,  $\frac{l-l_{g}}{l_{g}}=\frac{G}{S} \Rightarrow S=\frac{GI_{g}}{I-I_{g}}$

As I_g is very small, hence    $ S=\frac{GI_{g}}{I}$

 $b= \frac{(100)(1\times 10^{-3})}{10}=0.01$ Ω

A pipe open at both ensa has a fundamental frequency f in air. The pipe is dipped vertically in the water, so that half of it is in water, The fundamental frequency of the air column is now

Answer:

Explanation:

The fundamental frequency  of open pipe 

                          $f=\frac{v}{2l}$

  Now, after half-filled with water it becomes a closed pipe of length l/2

The fundamental frequency of this closed pipe.

                $f'=\frac{v}{4(\frac{l}{2})}$

                                   = $\frac{v}{2l}=f$

• Main 2016 - Physics 2016
• Main 2016 - Chemistry 2016
• Main 2016 - Mathematics 2016