Answer:
Option B
Explanation:
Let l0 be the unstretched length and l3 be the length under a tension of 9N. Then
Y = $\frac{4l_{0}}{A(l_{1}-l_{0})}$ = $\frac{5l_{0}}{A(l_{2}-l_{0})}$
= $\frac{9l_{0}}{A(l_{3}-l_{0})}$
These give
$\frac{4}{(l_{1}-l_{0})}$ = $\frac{5}{(l_{2}-l_{0})}$
l0 = 5l1 - 4l2
Further, $\frac{4}{(l_{1}-l_{0})}$ = $\frac{9}{(l_{2}-l_{0})}$
Substituting the value of l0 and solving, and we get l3 = 5l2 - 4l1