Answer:
Option B
Explanation:
Let l0 be the unstretched length and l3 be the length under a tension of 9N. Then
Y = \frac{4l_{0}}{A(l_{1}-l_{0})} = \frac{5l_{0}}{A(l_{2}-l_{0})}
= \frac{9l_{0}}{A(l_{3}-l_{0})}
These give
\frac{4}{(l_{1}-l_{0})} = \frac{5}{(l_{2}-l_{0})}
l0 = 5l1 - 4l2
Further, \frac{4}{(l_{1}-l_{0})} = \frac{9}{(l_{2}-l_{0})}
Substituting the value of l0 and solving, and we get l3 = 5l2 - 4l1