Answer:
Option A
Explanation:
Given,
(a) $2C+3H_{2} \rightarrow C_{2}H_{6}; \triangle H=-21.1 kcal$
(b) $C+O_{2} \rightarrow CO_{2}; \triangle H=-94.1kcal$
(c) $H_{2}+\frac{1}{2}O_{2} \rightarrow H_{2}O; \triangle H= -68.3 kcal$
Now, eqs, $2 \times (b) +3\times (c)-(a)$
$C_{2}H_{6}+\frac{3}{2}O_{2} \rightarrow 2CO_{2}+3H_{2}O$
Heat of combustion of ethane $\triangle x=2(-94.1)$
+3(-68.3)-(-21.1)
=$(-188.2)+(-204.9)-21.1$
=$-372 kcal$