Discussion Forum

The compound that  does not liberate CO₂, on treatment with aqueous sodium bicarbonate  solution is 

Answer:

Explanation:

 Plan    $NaHCO_{3}\rightleftharpoons Na^{+}+HCO_{3}^{-}$

 $HCO_{3}^{-}$   is decomposed by acid releasing CO₂

 $HCO_{3}^{-}+H^{+}\rightarrow H_{2}O+CO_{2}$

 If acid is stronger than $HCO_{3}^{-}$     then CO₂ is released 

 Phenol is less acidic and thus does not liberate CO₂   and NaHCO₃