Discussion Forum

A ray of light travelling in the direction   $\frac{1}{2}(\hat{i}+\sqrt{3}\hat{j})$  is inciodent on a plane mirror. after reflection, it travels along the  direction   $\frac{1}{2}(\hat{i}-\sqrt{3}\hat{j})$  . The angle of incidence is 

Answer:

Explanation:

Component along the plane=1/2  and component perpendicular to the plane = $\frac{\sqrt{3}}{2}$

 $\therefore$     $\tan i=\frac{(\frac{1}{2})}{(\frac{\sqrt{3}}{2})}=\frac{1}{\sqrt{3}}$

 $\therefore$     i= $30^{0}$   = angle of incidence