1)

Namita walks 14 metres towards the west, then turns to her right and walks 14 metres and then turns to her left and walks 10 metres. Again turning to her left she walks 14 metres. What is the shortest distance (in-metres) between, her-starting point and the present position ?


A) 10

B) 24

C) 28

D) 38

Answer:

Option B

Explanation:

262021734_dir 4.JPG 

Clearly, Namita'e distance from his initial position =AE = (AB + BE) = (AB + CD) =(14+10)m=24m.