Answer:
Option C
Explanation:
Force on moving charge while moving in a magnetic field is;
$\overrightarrow{F} = q (\overrightarrow{v} \times \overrightarrow{B})$ where $\overrightarrow{F}$ is perpendicular to $\overrightarrow{v}$ .
Work done/sec = $\overrightarrow{F}$.$\overrightarrow{v}$ = Fv cos90º= 0