Discussion Forum

The current in the 1Ω resistor shown in the circuit is

Answer:

Explanation:

Two 4Ω resistors are in parallel combination. Their equivalent resistance

= $\frac{4×4}{4+4}$ = $\frac{16}{8}$ = 2Ω

.'. Total resistance of the network = 2 + 1 = 3Ω

.'. Cunent through  1Ω resistor, i= $\frac{6}{3}$ = 2A