1)

If the differential equation for a simple harmonic motion is d2ydt2+2y=0, the time period of the motion is


A) π2 sec

B) 2sπ sec

C) π2 sec

D) 2π sec

Answer:

Option A

Explanation:

The differential equation of simple harmonic motion is

d2ydt2+2y=0 or d2ydt2=2y ...(i)

Standard equation of simple harmonic motion is

d2ydt2 =- ω2 y   ....(ii)

Comparing eq. (i) and (ii)

ω2 = 2 or ω = √2

As we know, 

ω=2πT

.'. TimePeriod, T = 2πω 

= 2π2π2 sec