Answer:
Option A
Explanation:
Total distance covered in 10 s = Area 1 + Area 2 + Area 3
$\frac{1}{2}\times6\times20+\frac{1}{2}\times2\times20+\frac{1}{2}\times2\times10$
= 90m
Total displacement in 10s = Area 1 - Area 2 +Area 3
$\frac{1}{2}\times6\times20- \frac{1}{2}\times2\times20+\frac{1}{2}\times2\times10$
= 50m