Discussion Forum



1)

The equivalent capacitance of the combination of the capacitors is

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A) 3.20µF

B) 7.80µF

C) 3.90µF

D) 2.16µF

Answer:

Option A

Explanation:

Equivalent capacitance of two parallel capacitors 10 μF and 6 μF = (10 + 6)μF = 16 μF . This 16 μF capacitor is in series combination with 4μF capacitor,

.'. Equivalent capacitance of the entire combination 

= $\frac{16\times4}{16+4} = \frac{64}{20}$

= 3.20μF