1) The ratio of the energies of the hydrogen atom in its first to second excited states is A) $\frac{1}{4}$ B) $\frac{4}{9}$ C) $\frac{9}{4}$ D) 4 Answer: Option CExplanation:1st excited state corresponds to n = 2 2nd excited state corresponds to n = 3 As E $\propto\frac{1}{n^{2}}$ $\frac{E_{1}}{E_{2}}$ = $\frac{n_2^2}{n_1^2}$ = $\frac{3^{2}}{2^{2}} = \frac{9}{4}$
