Physics | VITEEE 2019 | Discussion Page

The ratio of the energies of the hydrogen atom in its first to second excited states is

$\frac{1}{4}$

$\frac{4}{9}$

$\frac{9}{4}$

D) 4

Option C

1^st excited state corresponds to n = 2

2^nd excited state corresponds to n = 3

As E $\propto\frac{1}{n^{2}}$

$\frac{E_{1}}{E_{2}}$ = $\frac{n_2^2}{n_1^2}$

= $\frac{3^{2}}{2^{2}} = \frac{9}{4}$

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