1)

The value of the integral 31(|x|+|x1|)dx is


A) 4

B) 9

C) 2

D) 9/2

Answer:

Option B

Explanation:

|x|+|x1|={x(x1)=2x+1,ifx0x(x1)=1,if0x1x+(x1)=2x1,ifx1

.'.31(|x|+|x1|)dx =

01(2x+1)dx+101dx+31(2x1)dx

= [x2+x]01+[x]10+[x2x]31 =9