Mathematics | VITEEE 2019 | Discussion Page

It is given that the events A and B are such that P(A) = 1/4 , P(A/B) = 1/2 and P(B/A) = 2/3 then P(B) is?

$\frac{1}{6}$

$\frac{1}{3}$

$\frac{2}{3}$

$\frac{1}{2}$

Option B

P(A) = 1/4 , P(A/B) = 1/2 and P(B/A) = 2/3 then P(B)

By conditional probability

P(A∩B) = P(A)P(B/A) = P(B)P(A/B)

$\frac{1}{4}\times\frac{2}{3} = P(B)\times\frac{1}{2}$

P(B) = $\frac{1}{3}$

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