Discussion Forum

A wire 34 cm long is to be bent in the form of a quadrilateral of which each angle is 90°. What is the maximum area which can be enclosed inside the quadrilateral?

Answer:

Explanation:

Let one side of quadrilateral be x and another side be Y so, 2(x + Y) = 34 or,

(x+y) = 17   .....(i)

We know from the basic principle that for a given perimeter square has the maximum area, so, x = y and putting this value in equation (i)

x = y = 17/2=8.5

Area = x.y = 8.5× 8.5 = $72.25cm^{2}$