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If $(\overrightarrow{a}\times\overrightarrow{b})^{2}+(\overrightarrow{a}.\overrightarrow{b})^{2}$= 676 |$\overrightarrow{b}$| = 2 then |$\overrightarrow{a}$| is equal to

Answer:

Explanation:

Since,

$(\overrightarrow{a}\times\overrightarrow{b})^{2}+(\overrightarrow{a}.\overrightarrow{b})^{2}$ = 676

(|$\overrightarrow{a}$|.|$\overrightarrow{b}$|$\sin\theta\hat{n}$)² + (|$\overrightarrow{a}$|.|$\overrightarrow{b}$|$\cos\theta$)² = 676

|$\overrightarrow{a}$|² .|$\overrightarrow{b}$|² ($\sin^{2}\theta+\cos^{2}\theta$) = 676

|$\overrightarrow{a}$|² (2)² = 676 = |$\overrightarrow{a}$|²  =169

|$\overrightarrow{a}$|

=13