Discussion Forum

The area under the curve y = |cos x - sin x|, 0≤x≤$\frac{\pi}{2}$

Answer:

Explanation:

 y = |cos x - sin x|

Required area = $2\int_{0}^{\frac{\pi}{4}} (\cos x -\sin x)dx$

$2 \left[\sin x+\cos x\right]_0^\frac{\pi}{4}$ = $2 \left[\frac{2}{\sqrt{2}}-1\right]$

$2\sqrt{2}-2$