1)

If the coordinates at one end of the diameter of the circle x2 + y2 - 8x- 4y+ c = 0 are (-3, 2), then the coordinates at the other end are


A) (5,3)

B) (6,2)

C) (1,-8)

D) (11,2)

Answer:

Option D

Explanation:

The centre of the given circle is C = (4, 2) Let A = (-3,2)

1832021226_ockxzsshhmcv-s.png

If (α, β) are the coordinates of the other end of the diameter. then, as the middle point of the diameter is the centre,

$\frac{\alpha-3}{2}=4$ and $\frac{\beta+2}{2}=2$

$\Rightarrow\alpha=11,\beta= 2$

Thus, the coordinates of the other end of diameter are (11,2)