Discussion Forum



1)

For the reaction H2(g)+12O2(g)→H2O(l).ΔH = - 285.8 kJ/mol, ΔS = - 0.163kJ/molK.What is the value of free energy change at 27°C for the reaction?


A) -236.9kJ/mol

B) -281.4kJ/mol

C) -334.7kJ/mol

D) +334.7kJ/mol

Answer:

Option A

Explanation:

ΔG = ΔH - TΔS

T = 27+273 = 300K

ΔG = (-285.8) - 300(-0.163) kJ/mol

= -236.9kJ/mol