Discussion Forum

The wavelengths of the two photons are 2000Å and 4000Å respectively. What is the ratio of their energies?

Answer:

Explanation:

$E_{1}=h.\frac{c}{\lambda_{1}}$; $E_{2}=h.\frac{c}{\lambda_{2}}$

$\frac{E_{1}}{E_{2}} = \frac{hc}{\lambda_{1}}\times\frac{\lambda_{2}}{hc}$

= $\frac{\lambda_{2}}{\lambda_{1}}$ = $\frac{4000}{2000}$

= 2