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1)

The electrode potentials for Cu2+ (aq) + e- →  Cu+ (aq) and Cu+ (aq) + e- → Cu(s) are + 0. 15 V and + 0.50 V, respectively The value of E°Cu2+/Cu will be: 


A) 0.500V

B) 0.325V

C) 0.650V

D) 0.150V

Answer:

Option B

Explanation:

Cu2+  + 1e- →  Cu+    : ΔG°1 = -n11F

Cu+  +  1e- → Cu       :  ΔG2° = -n22F


Cu2++2eCu : ΔG=ΔG1+ΔG2

nEF=1n1

E1F+(1)n2E2F

nEF=F(n1E1+n2E2F)

E=n1E1+n2E2n

= 0.15×1+0.50×12 = 0.325V