1) The electrode potentials for Cu2+ (aq) + e- → Cu+ (aq) and Cu+ (aq) + e- → Cu(s) are + 0. 15 V and + 0.50 V, respectively The value of E°Cu2+/Cu will be: A) 0.500V B) 0.325V C) 0.650V D) 0.150V Answer: Option BExplanation:Cu2+ + 1e- → Cu+ : ΔG°1 = -n1E°1F Cu+ + 1e- → Cu : ΔG2° = -n2E°2F Cu2++2e−→Cu : ΔG∘=ΔG∘1+ΔG∘2 −nE∘F=−1n1 E∘1F+(−1)n2E∘2F −nE∘F=−F(n1E∘1+n2E∘2F) E∘=n1E∘1+n2E∘2n = 0.15×1+0.50×12 = 0.325V