Discussion Forum



1)

The value of KC for the reaction: A+3B $\rightleftharpoons$ 2C at 400ºC is 0.5.Calculate the value of KP


A) $1.6\times 10^{-4}$

B) $1.6\times 10^{-6}$

C) $1.6\times 10^{-5}$

D) $1.6\times 10^{-3}$

Answer:

Option A

Explanation:

KP = KC [RT]Δng    Δn = 2-4 = -2

T = 673K,  KC = 0.5,

R=0.082L.atm.mol-1 K-1

KP = 0.5×[0.082×673]-2

= $1.6\times 10^{-4}$