1) The value of KC for the reaction: A+3B ⇌ 2C at 400ºC is 0.5.Calculate the value of KP A) 1.6×10−4 B) 1.6×10−6 C) 1.6×10−5 D) 1.6×10−3 Answer: Option AExplanation:KP = KC [RT]Δng Δn = 2-4 = -2 T = 673K, KC = 0.5, R=0.082L.atm.mol-1 K-1 KP = 0.5×[0.082×673]-2 = 1.6×10−4
