1) For the reaction N2 + 3H2 → 2NH3 , If Δ[NH3]Δt=2×10−4mol/ls then value of −Δ[H2]Δt would be A) 1×10−4molL−1S−1 B) 3×10−4molL−1S−1 C) 4×10−4molL−1S−1 D) 6×10−4molL−1S−1 Answer: Option BExplanation: N2 + 3H2 → 2NH3 −Δ[N2]Δt = −13Δ[H2]Δt = 12Δ[NH3]Δt −Δ[H2]Δt = 32× Δ[NH3]Δt =32× 2×10−4mol/ls = 3×10−4molL−1S−1
