1) The horizontal component of the earth's magnetic field is 3.6x10-5 tesla where the dip angle is 60º. The magnitude of the earth's magnetic field is A) $2.8\times 10^{-4}$ tesla B) $2.1\times 10^{-4}$ C) $7.2\times 10^{-5}$ D) $3.6\times 10^{-5}$ Answer: Option CExplanation:Horizontal component of earth's field, H = B cos θ, since, θ = 60º 3.6 x 10-5 = B × 1/2 , B = 7.2 x 10-5 Tesla
