1) Two batteries of e.m.f 4V and 8V with internal resistance 1 Ω and 2Ω are connected in a circuit with a resistance of 9 Ω as shown in figure. The current and potential difference between the points P and Q are A) 1/3 A and 3 V B) 1/6A and 4 V C) 1/9 A and 9V D) 1/12 A and 12V Answer: Option AExplanation:$I = \frac{8-4}{1+2+9} = \frac{4}{12}= \frac{1}{3}A$ $V_{p} - V_{Q} = 4-\frac{1}{3}\times3 = 3V$
