Discussion Forum

1)

The equivalent capacitance between a and b for the combination of capacitors shown in figure where all capacitances are in microfarad is 

Answer:

Option A

Explanation:

Rearranging the circuits, we get the following circuit.

.'. equivalent capacitance between A and B

C_AB = $\frac{4\times4}{4+4} = 2\mu F$

and equivalent capacitance between C and D,

C_CD = $\frac{8\times8}{8+8} = 4\mu F$

C _ab= 2μF+4μF = 6μF