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In a common emitter transistor amplifier β = 60, R₀ = 5000 Ω and internal resistance of a transistor is 500 Ω. The voltage amplification of amplifier will be

Answer:

Explanation:

Voltage amplification

$A_{v} = \beta\frac{R_{0}}{R_{i}}$ = $60\times\frac{5000}{500}$ = 600