1) A unit vectorperpendicular to the plane formed by the points (1, 0, 1), (0,2,2) and (3, 3, 0) is A) 15√3(5ˆi−ˆj−7ˆk) B) 15√3(5ˆi−ˆj+7ˆk) C) 15√3(5ˆi+ˆj+7ˆk) D) None of these Answer: Option BExplanation:Let A(1, 0, 1), B(0, 2,2) andc (3, 3, 0) be the given points, then →AB=−ˆi+2ˆj+2ˆk, →BC=3ˆi+ˆj−2ˆk →AB×→BC=|ˆiˆjˆk−12131−2|=−5ˆi+ˆj−7ˆk .'. unit vector ⊥ to the Plane: ABC = ±15√3(−5ˆi+ˆj−7ˆk)