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 If at x = 1 the function x⁴ - 62x² + ax + 9 attains its maximum value on the interval [0, 2], then the value of a is

Answer:

Explanation:

Let f(x) = x⁴ - 62x² + ax + 9

$\Rightarrow f'(x) = 4x^{3} - 124x +a$

It is given that function f attains its maximum value on the interval [0, 2] at x = 1.

.'. f'(1) = 0 → 4 x 1³ - 124 x 1+ 1 = 0 

→ 4 - 124 + a = 0 → a = 120