1)

The two curves x3 - 3xy2 + 2 = 0 and 3x2y - y3 - 2 = 0 intersect at an angle of


A) π4

B) π3

C) π2

D) π6

Answer:

Option C

Explanation:

x33xy2+2=0

differentiating w.r.t. x :

3x23x(2y)dydx3y2=0

dydx=3x23y26xy and 3x2yy32=0

differentiating w.r.t. x:

3x2dydx+6xy3y2dydx=0

dydx=(6xy3x23y2)

Now, Product of slope

3x23y26xy× (6xy3x23y2)

.'. they are perpendicular. Hence, angle = π/2