Answer:
Option B
Explanation:
The sphere, x2+y2+z2=49 has centre at the origin (0, 0, 0) and radius 7.

DisTance of the plane 2x+3y−z−5√14=0
from the origin
|2(0)+3(0)−(0)−5√14|√22+32+(−1)2
= |−5√14|√14 = 5√14√14 = 5
Thus in Figure ; OP = 7, ON = 5
NP2 = OP2 - ON2 = 72 - 52 = 49 - 25 = 24
.'. NP = 2√6 Hence the radius of the circle = NP = 2√6