Discussion Forum

The value of the determinant Δ = $\begin{vmatrix}1 & 4& 3 \\0 & 12 & 9\\1 & 2 & 2 \end{vmatrix}$ is

Answer:

Explanation:

Δ = $\begin{vmatrix}1 & 4& 3 \\0 & 12 & 9\\1 & 2 & 2 \end{vmatrix}$

=  1(12 x 2 -2 x 9)-4 (0 x 2 - 1 x 9) + 3(0x 2 - 1 x12) = 1(24 - 18) - 4(0 - 9) + 3(0 - 12)

= 6 +36 - 36 = 6