1)

If A and B are events such that P(A) = 0.42, P(B) = 0.48 and P(A and B) = 0.16 then,

I    P(not A) = 0.58

II   P(not B) = 0.52

III   P(A or B) = 0.47

 

 


A) Only I and II are correct

B) Only II and III are correct

C) Only I and III are true.

D) All three statements are correct

Answer:

Option A

Explanation:

I .  P(notA) = 1 - 0.42 = 0.58

II .  P(not B) = 1 - P(B) = 1 - 0.48 = 0.52

III .  P(A or B) = P(A υ B) = P(A) + P(B) - P(A ∩ B) = 0.42 + 0.48 - 0.16 = 0.74