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1)

If 12cot2θ31Cosecθ+32=0, then the value of Sinθ is


A) 3/5 or 1

B) 2/3 or -2/3

C) 4/5 or 3/4

D) ± 1/2

Answer:

Option C

Explanation:

12cot2θ31Cosecθ+32=0

12(cosec2θ1)31Cosecθ+32=0

12cosec2θ31Cosecθ+20=0

12cosec2θ16Cosecθ15cosecθ+20=0

(4cosecθ5)(3cosecθ4)=0

Cosecθ=5/4,4/3sinθ=4/5,3/4