1) If 12cot2θ−31Cosecθ+32=0, then the value of Sinθ is A) 3/5 or 1 B) 2/3 or -2/3 C) 4/5 or 3/4 D) ± 1/2 Answer: Option CExplanation:12cot2θ−31Cosecθ+32=0 ⇒12(cosec2θ−1)−31Cosecθ+32=0 ⇒12cosec2θ−31Cosecθ+20=0 ⇒12cosec2θ−16Cosecθ−15cosecθ+20=0 (4cosecθ−5)(3cosecθ−4)=0 Cosecθ=5/4,4/3∴sinθ=4/5,3/4