Chemistry | VITEEE 2018 | Discussion Page

Given that the equilibrium constant for the reaction $2SO_{2}+ O_{2}\rightleftharpoons 2SO_{3}$ has a value of 278 at a particular temperature. What is the value of the equilibrium constant for the following reaction at the same temperature?

$SO_{3} \rightleftharpoons SO_{2} + 1/2O_{2}$

$1.8\times10^{-3}$

$3.6\times10^{-3}$

$6\times10^{-2}$

$1.3\times10^{-5}$

Answer:

Option C

Explanation:

$2SO_{2}+ O_{2}\rightleftharpoons 2SO_{3}$ K = 278 (given)

$SO_{3} \rightleftharpoons SO_{2} + 1/2O_{2}$ K' = $\left(\sqrt{\frac{1}{K}}\right)$

= $\left(\sqrt{\frac{1}{278}}\right)$ = $\sqrt{35.97\times10^{-4}}=6\times10^{-2}$

Discussion Forum

Answer:

Explanation: