Discussion Forum



1)

Given that the equilibrium constant for the reaction $2SO_{2}+ O_{2}\rightleftharpoons 2SO_{3}$ has a value of 278 at a particular temperature. What is the value of the equilibrium constant for the following reaction at the same temperature?

$SO_{3} \rightleftharpoons SO_{2} + 1/2O_{2}$


A) $1.8\times10^{-3}$

B) $3.6\times10^{-3}$

C) $6\times10^{-2}$

D) $1.3\times10^{-5}$

Answer:

Option C

Explanation:

$2SO_{2}+ O_{2}\rightleftharpoons 2SO_{3}$ K = 278 (given)

$SO_{3} \rightleftharpoons SO_{2} + 1/2O_{2}$ K' = $\left(\sqrt{\frac{1}{K}}\right)$

= $\left(\sqrt{\frac{1}{278}}\right)$ =$\sqrt{35.97\times10^{-4}}=6\times10^{-2}$