Chemistry | VITEEE 2018 | Discussion Page

The energies E₁ and E₂ of two radiations are 25 eV and 50 eV respectively. The relation between their wavelengths i.e., λ₁ and λ₂ will be :

$\lambda_{1}=\lambda_{2}$

$\lambda_{1}=2\lambda_{2}$

$\lambda_{1}=4\lambda_{2}$

$\lambda_{1}=1/2\lambda_{2}$

Option B

Given E₁= 25 eV E₂ = 50 eV

$E_{1} = \frac{hc}{\lambda _{1}}$ $E_{2} = \frac{hc}{\lambda _{2}}$

$\therefore \frac{E_{1}}{E_{2}} = \frac{\lambda_{2}}{\lambda_{1}}$

$\therefore \frac{\lambda_{2}}{\lambda_{1}} = \frac{25}{50}$ = 1/2

$\therefore \lambda_{1}=2\lambda_{2}$

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