1) The resistance of 0.01 N solution of an electrolyte was found to be 220 ohm at 298 K using a conductivity cell with a cell constant of 0.88cm-1. The value of equivalent conductance of solution is - A) $400 mho$ $cm^{2} g$ $ eq^{-1}$ B) $295 mho$ $cm^{2} g$ $ eq^{-1}$ C) $ 419 mho$ $cm^{2} g$ $ eq^{-1}$ D) $425 mho$ $cm^{2} g$ $eq^{-1}$ Answer: Option AExplanation:$Λ_{eq}=K\times\frac{1000}{N}=\frac{1}{R}\times\frac{l}{a}\times\frac{1000}{N}$ = $\frac{1}{R}\times Cell constant\times\frac{1000}{N}$ = $\frac{1}{220}\times0.88\times\frac{1000}{0.01}$ = $400 mho$ $cm^{2} g$ $eq^{-1}$
