Chemistry | VITEEE 2018 | Discussion Page

The resistance of 0.01 N solution of an electrolyte was found to be 220 ohm at 298 K using a conductivity cell with a cell constant of 0.88cm^-1. The value of equivalent conductance of solution is -

$400 mho$

$cm^{2} g$

$eq^{-1}$

$295 mho$

$cm^{2} g$

$eq^{-1}$

$419 mho$

$cm^{2} g$

$eq^{-1}$

$425 mho$

$cm^{2} g$

$eq^{-1}$

Answer:

Option A

Explanation:

$Λ_{eq}=K\times\frac{1000}{N}=\frac{1}{R}\times\frac{l}{a}\times\frac{1000}{N}$

= $\frac{1}{R}\times Cell constant\times\frac{1000}{N}$

= $\frac{1}{220}\times0.88\times\frac{1000}{0.01}$

= $400 mho$ $cm^{2} g$ $eq^{-1}$

Discussion Forum

Answer:

Explanation: